# Simulation of Starbucks

Project Statement 1

Simple Layout of the Starbucks 1

Data Collection and Analysis 1

Inter Arrival Time 3

Service at the Counter 4

Service Time for Barista 1 5

Service Time for Barista 2 6

Observation Table …………………………………………………………………………………………………………………………………….7

Project Statement

Starbucks is the largest coffee house company in the world. They have over 16,000 stores in over 50 countries. We have one of their outlets in our university. We chose to carry out our simulation project on this particular store because it would be ideal to study a system which has a queue at any time during its working hours. It would also help the company in serving their customers more efficiently and

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he input analyzer was then opened. The data was opened using the input analyzer. After this the curve was fit for the inter-arrival time. The histogram was created with 11 intervals. The best fit was a Beta distribution with a p-value of 0.515. The next best values were also checked and it was noticed that Exponential and Gamma distribution with a p-value of 0.184 were the next best. The Weibull with a p-value of 0.139 was next. For analysis purpose, the number of intervals of the histogram was reduced to ten. It was realized that the best fit was an exponential distribution with a p-value of 0.708. This was taken as the inter-arrival time as the other distributions had a lower p-value. The mean was found to be 56.4 seconds. The next best were Gamma with p-value 0.515, Erlang and Weibull with a p-value of 0.496 and Beta with a p-value of 0.171. The result of the input analyzer for the inter-arrival time was then saved.

Next, the data of the service time at the bill counter was filled and saved in the notepad and was opened using the input analyzer. The best fit option was used. It was noted that the best fit was the Erlang distribution with a p-value of 0.0445 and the mean was found to be 31.1 seconds. The number of intervals was 11. On changing the number of intervals to ten changed the same Erlang distribution to a p-value of 0.00982. Therefore, it